## QUANTITATIVE REASONING TESTS & HOW TO PASS THEM INCLUDING SAMPLE TEST QUESTIONS AND ANSWERS

Learn how to pass Quantitative Reasoning Tests with this comprehensive 229-page guide which is suitable for UKCAT candidates and anyone who is required to take all types of Quantitative Reasoning tests. ## What are Quantitative Reasoning Tests?

Quantitative Reasoning tests assess a candidate’s ability to problem solve using numerical skills. Therefore a candidate is expected to be confident with numbers to a good GCSE standard. However, a higher ability to problem solve is more beneficial than numerical facility.

The main purpose of Quantitative Reasoning tests are assess to assess students and discover whether or not they have the necessary skills for understanding the the potential types of quantitative arguments that they may have in their professional career.

## WHERE ARE QUANTITATIVE REASONING TESTS USED FOR?

Quantitative Reasoning is a skill that has practical applications and is slightly different to mathematics.

For example, a mathematician will often be using the language of mathematics, which is often a language of it’s own. However an everyday person can apply Quantitative Reasoning in an everyday language though logic on data interpretation.

Job roles in the medical profession such as dentists or doctors will often find themselves needing to analyse data and apply it in a practical level.

This is why Quantitative Reasoning tests are a big part of the UK Clinical Aptitude Test (UKCAT). The purpose of the UKCAT obtain a greater fairness in entering medicine and dentistry. In this aspect, candidates will be tested on his or her ability to solve numerical problems. You will be given 24 minutes to go through 9 tables, graphs, charts as information and then answer 36 questions within the range.

Many universities and colleges have entrance and placement tests based on Quantitative Reasoning such as the University of Kent or Columbia University.

Quantitative Reasoning tests are used more commonly during technical assessments such as roles within the medical profession and roles where a high degree of problem-solving capability is required. The test assesses your ability to use numerical skills in order to accurately solve problems. Those sitting the test will normally be familiar with numbers to a good standard at GCSE level.

During many Quantitative tests the candidate will be permitted to use a calculator. More often than not the calculator will either be supplied by the test administrators or an online version will be supplied. It is therefore very important that you confirm with the test administrator the type of calculator that will be supplied prior to the test so that you can familiarise yourself with it.

To help you get started in your preparation, let us take a look at a couple of quantitative reasoning test questions and answers.

## Quantitative Reasoning Sample Questions

PRACTICE QUESTION 1

Here is some information about the costs of purchasing land. Prime farmland is £7,500 per acre. Building land is £1.1 million per hectare.

1 hectare = 10,000 m2 = 2.47 acres

A plot of building land is square. The length of one side of the plot is 80m.

Which one of the amounts below is closest in value to the cost of buying the plot?

A. £704,000
B. £568,000
C. £850,000
D. £902,000
E. £400,000

PRACTICE QUESTION 2

A square field, S, has an area greater than 3,600 m2. Its length is increased by 10m and its width decreased by 10m to give a rectangular field, R. Which one of the following is true?

A. Area S > area R and perimeter S = perimeter R

B. Area S = area R and perimeter S = perimeter R

C. Area S = area R and perimeter S < perimeter R

D. Area S < area R and perimeter S < perimeter R

E. Area S < area R and perimeter S < perimeter R

First you need to multiply 80 by 80 to give you the
area:
• 80 x 80 = 6,400m2
Converting 6,400m2 to hectares = 6,400 ÷ 10,000 = 0.64 hectares
Multiply this by the price of building land:
• 0.64 x 1,100,000 = £704,000

Step 1 = If the area is approximately 3600m2, the square root of that would be 60m (square field S).

Step 2 = If the length is increased by 10m and its width decreased by 10m to give a rectangular field R, it will make field R 70m by 50m.

Step 3 = Therefore the area of S will be larger (>) than area R.

Step 4 = The perimeters of both field would still be the same, so therefore perimeter S = perimeter R MAIN PRODUCT FEATURES:

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